\(C=\dfrac{2^6\cdot3^{10}}{3^9\cdot2^6}=3\\ D=\dfrac{3^{24}\cdot3^{10}}{3^{21}\cdot3^{11}}=\dfrac{3^{34}}{3^{32}}=3^2=9\\ F=\dfrac{2^{45}\cdot5^{14}}{5^{15}\cdot2^{47}}=\dfrac{1}{2^2\cdot5}=\dfrac{1}{20}\\ G=\dfrac{2^2\cdot5^2\cdot5^3}{2^3\cdot5^4}=\dfrac{1\cdot5}{2}=\dfrac{5}{2}\)

C=3

D=9

F=1/20

G=5/2

Em ko giải chi tiết vì nó lâu

Mong thông cảm!

C= \(\dfrac{8^2.9^5}{3^9.4^3}\)

   = \(\dfrac{\left(2^3\right)^2.\left(3^2\right)^5}{3^9.\left(2^2\right)^3}\)

   = \(\dfrac{2^6.3^{10}}{3^9.2^6}\)

   = \(\dfrac{3^1}{1}\)

   = \(\dfrac{3}{1}\)

Tách từng câu ra giùm, như này ai giải nổi:)))))

13*(-7)=-91

(-8)*(-25)=200

Học tốt

13 . (-7) = -91

(-8) . (-25) = 200

25 . (-47) . (-4) = 4700

8. (125 - 3000) = 8. (-2875) = -23000

Hok tốt !

\(1\dfrac{13}{15}.0,75-\left(\dfrac{8}{15}+25\%\right).\dfrac{24}{47}-3\dfrac{12}{13}:3\)

\(=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{8}{15}+\dfrac{1}{4}\right).\dfrac{24}{47}-\dfrac{51}{13}:3\)

\(=\dfrac{7}{5}-\dfrac{47}{60}.\dfrac{24}{47}-\dfrac{17}{13}\)

\(=\dfrac{7}{5}-\dfrac{2}{5}-\dfrac{17}{13}\)

\(=1-\dfrac{17}{13}=-\dfrac{4}{13}\)

125/90=25/18

84/91=12/13

75/45=25/15=5/3

125/90=25/18

84/91=12/13

75/45=25/15=5/3

6/7=18/21=54/63=104/126

125/90 = 25/18 

84/91 = 12/13

75/45 = 25/15 = 5/3

6/7 = 18/21 = 54/63 = 108/126

13 . ( - 7 ) = - 91

( - 8 ) . ( - 25 ) = 200

25 . ( - 47 ) . ( - 4 ) = ( - 100 ) . ( - 47 ) = 4700

8 . ( 125 - 3000 ) = 8 . 125 - 3000 = 1000 - 3000 = - 2000

512 . ( 2 - 128 ) - 128 . ( - 512 ) = 512 . ( 2 - 128 + 128 ) = 512 . 2 = 1024

13 x (-7) = -91

(-8) x (-25) = 200

25 x (-47) x (-4) = 4700

8 x (125 - 3000) = -23000

512 x (2 - 128) - 128 x (-512) = 1024

Nếu sai thì thôi

Học tốt!!!

1)
\(=\dfrac{\left(2.3\right)^{20}.\left(5^2\right)^{19}}{\left(2^3\right)^7.\left(3^2\right)^{10}.\left(5^3\right)^{13}}\)
\(=\dfrac{2^{20}.3^{20}.5^{38}}{2^{21}.3^{20}.5^{39}}\)
\(=\dfrac{1}{2.5}\)
\(=\dfrac{1}{10}\)

8^15 . 25^7                                  (2^3) ^ 15  . (5^2) ^ 7             2^45. 5^17                   5^2         25 

________________             =   ___________________    = ________________    =  ___  =   _____

125^5 . 2^47                                (5^3) ^5 .  2^47                     5^15 .  2^47                   2^2           4

\(\frac{8^{15}\cdot25^7}{125^5\cdot2^{47}}=\frac{\left(2^3\right)^{15}\cdot\left(5^2\right)^7}{\left(5^3\right)^5\cdot2^{47}}=\frac{2^{45}\cdot5^{14}}{5^{15}\cdot2^{47}}=\frac{1\cdot1}{5\cdot2^2}=\frac{1}{5\cdot4}=\frac{1}{20}\)

\(\frac{8^{15}.25^7}{125^5.2^{47}}=\frac{\left(2^3\right)^{15}.\left(5^2\right)^7}{\left(5^3\right)^5.2^{47}}\)

\(=\frac{2^{45}.5^{14}}{5^{15}.2^{47}}=\frac{1}{5.2^2}\)

\(=\frac{1}{5.4}\)

\(=\frac{1}{20}\)

a) \(=300\)

b) \(=374\)

c) \(=4747\)

d) \(=180000\)

a)300

b)374

e)7000